已知函数f(x)=x2+ax(x≠0 a∈R).(1)判断函数f(x)的奇偶性;(2)当x∈[2 +
已知函数f(x)=x2+ax(x≠0,a∈R).(1)判断函数f(x)的奇偶性;(2)当x∈[2,+∞)时,若f(x)是增函数,求实数a的取值范围.
参考解答
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2024-03-19 06:13:13
参考答案：(1)当a=0时,f(x)=x2为偶函数;当a≠0时，f(x)=x2既不是奇函数也不是偶函数。(2)(-∞,16
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